But we're not picking 3 numbers from 70...
we're picking 3 numbers from the 5 picked from 70.
How many ways can you draw three numbers from 70?
N = 70! / (70-3)!/3! = 54,740
How many valid three number combinations can a set of five numbers contain?
M = 5! / (5-3)! / 3! = 10
(If the five numbers were 1-2-3-4-5, valid combinations would be: 5-4-3, 5-4-2, 5-4-1, 5-3-2, 5-3-1, 5-2-1, 4-3-2, 4-3-1, 4-2-1, 3-2-1)
So the odds of drawing one of the 10 sets of valid triplets from 54,740 is:
1:5,474.
Math isn't mine...it's a friend of mine's math.
