Originally Posted by NectarDetector
In a perfect situation with both coins laying flat, yes... but how much of detecting is prefect situations?
Dimes seem to hit much harder than pennies on all of my machines...so unsure how you came to your conclusopms that the penny will induce a stronger response...
I find more dimes than anything! lol
Define "much harder". Do you mean a higher VDI? VDI isn't determined by the strength of the target signal. Coin silver is more conductive than a bronze and brass. Clad coins have an effective conductivity that is higher than bronze or brass. If you look at two targets of the relatively same diameter, thickness and shape, the target with the higher conductivity will have the bigger VDI number.
How can I conclude that a penny will induce a stronger response? Math. If the math said Dimes produce a stronger field, our detector manuals would show that on average you can find a dime deeper than a penny. Can you detect a flat dime deeper than a penny on edge? Sure. However, all conditions the same - same orientation, ground conditions, detector settings, etc, etc - you will be able to pick up the penny at a greater depth than you can the dime. That is what is meant by stronger response.
Let's take this up a notch. A clad quarter and dime, or a barber quarter and dime are made of the same respective alloys. Why is it you can find quarters deeper than you can find the dime? It is because the quarters are wider and thicker than the dimes are. Because of this size difference, the quarter will generate an induced magnetic field that is stronger than than dime at the same depth. A dime the size of a penny would be detectable deeper than a penny. A penny the size of a dime would not detected as deep as the dime would.
A dime at 15" is still going to generate an induced field. However, it is going to be so weak that the receive coil won't even notice it.